function getElementsByClass(searchClass, domNode, tagName) {
     if (domNode == null) domNode = document;
     if (tagName == null) tagName = '*';
     var el = new Array();
     var tags = domNode.getElementsByTagName(tagName);
     var tcl = " "+searchClass+" ";
     for(i=0,j=0; i<tags.length; i++) {
          var test = " " + tags[i].className + " ";
          if (test.indexOf(tcl) != -1)
               el[j++] = tags[i];
          }
     return el;
}
 
var hidden = false;
function toggle_hideme1() {
     hidden = !hidden;
     var newDisplay;
     if(hidden) {
          newDisplay = 'block';
     }
     else
     {
          newDisplay = 'none';
     }
     var showfirst = getElementsByClass("div_class_name", null, "div");
     for(var i = 0; i < showfirst.length; i++) {
          showfirst[i].style.display = newDisplay;
     }
}
 
var hiddenb = false;
function toggle_hideme2() {
     hiddenb = !hiddenb;
     var newDisplay;
     if(hiddenb)
     {
          newDisplay = 'block';
     }
     else
     {
          newDisplay = 'none';
     }
     var showsecond = getElementsByClass("div_class_name", null, "div");
     for(var k = 0; k < showsecond.length; k++) {
          showsecond[k].style.display = newDisplay;
     }
}

For the variables ‘showfirst’ and ‘showsecond’ you can call them what ever you want, just make sure they stay the same in only one function, not two. Be sure to change ‘div_class_name’ to a custom name for each field.

Also, these are setup to be hidden first, you can change that by swapping the ‘newDisplay = ‘ lines.

For the HTML code we are going to use check boxes. We need two boxes each with names that call the function.

<input type="checkbox" name="showone" id="showone" value="showone" onClick="toggle_hideme1('showone');"><br />
<input type="checkbox" name="showtwo" id="showtwo" value="showtwo" onClick="toggle_hideme2('showtwo');"><br />

If you want the boxes checked to start first swap the ‘newDisplay =’ lines, and use this.

<input type="checkbox" name="showone" id="showone" value="showone" onClick="toggle_hideme1('showone');" CHECKED><br />

As in my previous post you need to put what ever will be shown or hidden in a div class tag.

<div class="div_class_name" style="display: none;">

The style hides everything in the class until the box is checked.

That will start the boxed checked, when you un-check it the data in all div classes with that name will hide (remember the ‘div_class_name’? that’s what we are working with).

I wrote this up in just a couple minutes, so I truly help it makes scene. You can check out an example of how it works here.

I start with creating the DB. Lets call the table ‘phone’. We need 3 rows. ‘idx’ int(10) with Auto Increment and primary key. ‘name’ varchar(30), and ‘numb’ varchar(20). You can setup the db how ever you choose. I create the idx so that I have a key field.

Now we need some javascript.

var counter = 0;
Start a counter. Yes, at 0
function add_phone() {
    counter++;
// I find it easier to start the incrementing of the counter here.
    var newFields = document.getElementById('add_phone').cloneNode(true);
    newFields.id = '';
    newFields.style.display = 'block';
    var newField = newFields.childNodes;
    for (var i=0;i<newField.length;i++) {
        var theName = newField[i].name
        if (theName)
                newField[i].name = theName + counter;
// This will change the 'name' field by adding an auto incrementing number at the end. This is important.
        }
        var insertHere = document.getElementById('add_phone');
// Inside the getElementById brackets is the name of the div class you will use.
        insertHere.parentNode.insertBefore(newFields,insertHere);
}

Now I like to put that in a seperate .js file, but you can add it to your HTML HEAD tag.

Next we need to build the form.

<form name="add_a_phone" action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" enctype="multipart/form-data">
<fieldset>
<div id="phone">
    <input type="text" name="phone_0" value="" />
    <input type="text" name="phone_num_0" value="" /><br>
</div>
<div id="add_phone" style="display: none;">
    <input type="text" name="phone_" value="" />
    <input type="text" name="phone_num_" value="" /><br>
</div>
<input type="button" id="add_phone()" onclick="add_phone()" value="Give me more fields!" /><br>
<input type="submit" name="submit" value="submit" />
</fieldset>
</form>

Notice how in the input button field that the ‘id’ and ‘onclick’ are the same. That’s important, and yes you do need the brackets for some reason.
Also note that the form name can NOT be the same as any div id!!! I keep making that mistake.
You will need some way of checking how many fields were added when you get to your ‘if(isset($_POST[‘submit’))’ statement. This gets a little messy.
Because I like my forms to go back to this page and check if submit was clicked we need to put some php code at the very top.

<?php
    if(isset($_POST['submit']))
    {
        echo "You clicked submit!<br>";
        echo "Here is your data<br>";
        echo "<br>";
        if ($_POST['phone_num_0'])
        {
                $continue = FALSE;
                $i = 0;
                while ($continue == FALSE)
                {
                    if (isset($_POST['phone_'.$i]))
                    {
                    echo $_POST['phone_'.$i] . " = " . $_POST['phone_num_'.$i] . "<br>";
                    $phone = $_POST['phone_'.$i];
                    $phone_num = $_POST['phone_num_'.$i];
                    $query = "INSERT INTO phone (idx, name, numb) VALUES ('NULL', '$phone', '$phone_num')";
                    $result = mysql_query($query);
                }
                else
                {
                    $continue = TRUE;
                }
                $i++;
            }
        }
    }
?>

Obviously I left out some information. Like connecting to your DB. I’m assuming you already know how to do that.

I first wrote this on my main page. This post is almost a copy/paste from the main page. I like adding it to the blog since it gets better indexing from search engines and hopefully the information will be useful to you. On the main page there is also a working example so you can see how it all ties in. Check it out Here

Questions?

After scouring the net for information I finally got my answer from JimmySeal at TechGuy.org. Turns out the process is very simple.

In my first example I want to hide just one div tag when a check box is clicked. The process is a simple one, all we need to do is create a div with an id argument. Like div id=”hideme”. I prefer to use external js files to hold my javascript functions. Lets call it junctions.js. In this file lets put this bit of code.

function toggle_visibility(hideme)
{
	var e = document.getElementById(hideme);
	if(e.style.display == 'block')
		e.style.display = 'none';
	else
		e.style.display = 'block';
}

This will hide the div tag with id hideme
So in my html file I have something like this. (My example is in an input form)

<b>Show the field</b><input type="checkbox" name="a_name" value="a_name" onClick="toggle_visibility('hideme');">
<div id="hideme" style="display:block;">
	<b>was hidden</b><textarea name="some_name" cols="40" rows="5"></textarea><br />
</div>

Notice that the div id and the onClick functions are the same name, hideme. That’s it! How when the box is checked it will hide that one div tag.

What if you want to hide multiple div tags. Unfortunately the above script will not work simply because you can’t have more than one div id per page. You must use div class.

Open up your functions.js file and put this in.

var hidden = false;
function getElementsByClass(searchClass, domNode, tagName) {
	if (domNode == null) domNode = document;
	if (tagName == null) tagName = '*';
	var el = new Array();
	var tags = domNode.getElementsByTagName(tagName);
	var tcl = " "+searchClass+" ";
	for(i=0,j=0; i<tags.length; i++) {
		var test = " " + tags[i].className + " ";
		if (test.indexOf(tcl) != -1)
		el[j++] = tags[i];
	}
	return el;
}
 
function toggle_hideme()
{
	hidden = !hidden;
	var newDisplay;
	if(hidden)
	{
		newDisplay = 'none';
	}
	else
	{
		newDisplay = 'block';
	}
	var hellos = getElementsByClass("div_class_name", null, "div");
	for(var i = 0; i < hellos.length; i++)
	{
		hellos[i].style.display = newDisplay;
	}
}

Now for the form code example

<input type="checkbox" name="a_name" value="a_name" onClick="toggle_hideme('div_class_name');">
<div class="div_class_name">
	Blah Blah Blah
</div>
<div class="something_else">
	What ever is here will not disappear!
</div>
<div class="div_class_name">
	more blah blah blah
</div>

The only thing you need to pay attention to here is div_class_name just change it to what ever you want to call your div tag.

EDIT NOTE:
I just want to say that I’ve been getting a lot of hits here, but no one leaves me any comments. How do I know if this is helpful? Please leave a comment. I won’t sell your e-mails or anything. If you so desire enter in a fake e-mail, I don’t care. I just want to know. Thank you.

UPDATE!
http://blog.tangorangers.com/2009/08/using-javascript-to-hide-singlemultiple-div-tags-with-the-same-name-part-2/

The only way this post will help you is if in your MySQL database you have NULL set to YES and DEFAULT as NULL. Most databases are not setup this way, it’s probably pretty rare. See end of post.

Recently I ran into an issue with my php script that inserts data into MySQL that has NULL fields. Here is how I fixed it.

To start in my database I have fields that can accept a NULL value, because of this I had to change the way my data was entered into the database. After I created a form to take the data I then ran it through a process to add slashes (in case there were any single quotes, double quotes, or any other non standard character).

For example, I have a field called title in my database, and in my form. Now lets say that the user of the script doesn’t enter in a title but we still want to insert a record. I need to first determine that there is or is not any data.

if ($_POST['title'])
{
     $title = addslashes($_POST['title']);
}
else
{
     $title = "NULL";
}

Notice that I put NULL in quotations. If you do not quote it you will clear out the variable. This will cause issues in the INSERT query to MySQL.

The MySQL query might look something like this.

$result = mysql_query($query = "INSERT INTO table_name (name, title) VALUES ('$name', '$title')");

I know this doesn’t make much sense, but it’s the way I had to do it because of the way my database was setup. Here is the entire php file.

<?php
if (isset($_POST['submit']))
{
  if (isset($_POST['name']))
  {
    $name = addslashes($_POST['name']);
    if (isset($_POST['title']))
    {
      $title = addslashes($_POST['title']);
    }
    else
    {
      $title = "NULL";
    }
  $result = mysql_query($query = "INSERT INTO table_name (name, title) VALUES ('$name', '$title')");
  }
  else
  {
    echo "Enter a Name!<br />";
  }
}
?>
<form name="form1" action = "<?php echo $_SERVER['PHP_SELF']; ?>" method="post" enctype='multipart/form-data'>
     <input name="name" type="text" value="name" />
     <input name="title" type="text" value="title" />
     <input name="submit" type="submit" value="submit" />
</form>

In the Database, using something like PHPMyAdmin you might see something like this.

Field———-Type—————–Collation———Attributes——Null——Default——Extra
name——-varchar(30)—-utf8_unicode_ci——–None———-No
title———varchar(30)—-utf8_unicode_ci——–None———-Yes——–NULL

If so you will need to quote your NULL before inserting the data into MySQL. (Sorry that doesn’t line up very well)
Maybe this way will help.

First, the only real requirement is PHP and a web server (I use Apache).

Create a new file, lets call it ‘image_upload.php’
At the bottom of the page we are going to put in a basic form to give a browse and upload button.

<form action="./image_upload.php" enctype="multipart/form-data" method="post">
Select Image to upload
<input name="thefile" type="file" />
<input name="submit" type="submit" value="upload" />
</form>

The form name isn’t important. The action is. That is the name of the file that needs to be accessed when the upload button is clicked.
Input type is very important, and so is the name.

Now that we have a starting point go to the top of the file. Just to make it easy I’m going to paste the entire code here then explain it part by part.

if(isset($_POST['submit']))
{
 
	$tmp_name = $_FILES['thefile']['tmp_name'];
	$newarray = explode( ".", $_FILES['thefile']['name']);
	$thecount = count($newarray);
	$fileprefix = time() . "." . $newarray[$thecount - 1];
	move_uploaded_file($tmp_name, "../img/$fileprefix");
	exit();
}

To start the if statement at the top is to ensure that the ‘submit’ button was hit before running the script.
The ‘$tmp_name‘ variable is used to get rid of that damn array.
$newarray takes the file’s real name (see note below) and explodes the array into several smaller arrays by the ‘.’. For example, if the file uploaded it called ‘best.friends.pic.jpg’ it breaks that name up to ‘best’, ‘friends’, ‘pic’, and ‘jpg’. Trust me, this is important (If you don’t understand how arrays work I recommend doing some research and learning).
The next line I use the count function. This will help in the event there is more than one ‘.’ in the name of the file being uploaded.
Now to create the new name of the file. $fileprefix equals the time of the upload. This works well, it will grab the time from the server and use it for the file name. Then it adds a ‘.’, then adds the suffix of the file (example: jpg)
Time to move the uploaded file. In my example I added the directory before the newly created file name. This will go back 1 directory and then to ‘img/‘.
Lastly, we use the ‘exit();‘ function. This is so that after the file has been uploaded the script stops. If you remove the function it will display the upload form again.

NOTE: There is a reason (altho I don’t know it) on why there are 2 arrays. It seems to me that the first ($_FILES['thefile']['tmp_name']) holds 2 parts, a pointer for ‘thefile‘ and the temp name php gives files before we do something with it, and the second ($_FILES['thefile']['name']) contains the original name of the file.

btw, make sure apache has full access to the folder you are uploading images to.
For example, if this is on your own server check /etc/apache.conf (or httpd.conf) for the user and group apache runs under. This is usually either ‘nobody‘ or ‘apache‘.
If you have SSH into your server (or are sitting infront of it) goto the directory your files are being sent to and type

chown apache.apache img/ -R

This will give both user and group ‘apache‘ access to write files.

p.s. I will be creating another script here that deals with multiple picture uploads.